Question

Give all the steps necessary to obtain 100 mL of a 1.9 X 10 -5 M solution using serial dilution. The required laboratory equipment and compound information are given:0.15 grams of a compound with a molar mass of 793 g/mol, deionized water, 1.0 mL pipette, 5.0 mL pipette, 10.0 mL pipette and two - 100.0 mL volumetric flasks

Answer 1

Take 10.0mL of stock solution using 10.0mL pipette in a 100mL volumetric flask and make up the solution with deionized water up to the mark of the flask and we get 100mL of 1.9×10⁻⁵M solution.

Step-by-step explanation:

Molarity of stock solution,
`M = (mass)/(Molar mass) * (1)/(Volume (L))`

`M = (0.15g)/(793mol^(-1)) * (1)/(1.0L) = 1.9*10^(-4)M`

According to law of dilution MV = m'v'

Where, M = Molarity of stock solution = 1.9×10⁻⁴M

V = Volume of stock solution = ?

m' = Molarity of dilute solution = 1.9×10⁻⁵M

v' = Volume of dilute solution = 100 mL

Substituting the above parameters in the equation of dilution

`V = (m'v')/(M)`

`V = 10.0 mL`