Question

If 130.0 g of steam at 200.0 °C absorbs 900.0 kJ of heat energy, what will be its increase in temperature?

Help pleaseeeeee

Answer 1

t=1855.45 C

Step-by-step explanation:

m=0.13kg t1=200C H=900000J Cp=4182J/kgC

h=m*cp*change in temperature

900*10^3=0.13*4182*(T-200)

1655.45=t-200

t=1855.45 C