Question

Find the area and perimeterof a square with a side length of
`2√(3) + 6√(7)` inches

Answer 1

Explanation:

area=side ²=(2√3+6√7)²=4×3+36×7+2×2√3×6√7=12+252+24√21=264+24√21

Answer 2

Explanation:

Perimeter

P = 4s

P = 4*(2*sqrt(3) + 6*sqrt(7) )

P = 8*sqrt(3) + 24*sqrt(7)

Area

A = s^2

A = (2sqrt(3) + 6sqrt(7) )(2 sqrt(3) + 6sqrt(7) )

F:= (4*sqrt(3)^2 = 16 * 3 = 48

O:= 2sqrt(3) * 6sqrt(7) ) = 12sqrt(21)

I := 6*sqrt(7)*2 sqrt(3) = 12 sqrt(21)

L:=6*sqrt(7) ^2 = 36 * 7 = 252

The answer is 300 + 24*sqrt(21)