Answer:
0.53g
Step-by-step explanation:
We'll begin by converting 175mL to L. This is illustrated below:
1000mL = 1L
Therefore 175mL = 175/1000 = 0.175L
Next, we shall calculate the number of mole of O2 that occupy 0.175L. This is illustrated below:
1 mole of O2 occupy 22.4L at stp.
Therefore, Xmol of O2 will occupy 0.175L i.e
Xmol of O2 = 0.175/22.4
Xmol of O2 = 7.81×10¯³ mole
Therefore, 7.81×10¯³ mole of O2 occupy 175mL.
Next, we shall determine the number of mole of H2O2 that decomposed to produce 7.81×10¯³ mole of O2. This is illustrated below:
2H2O2 —> 2H2O + O2
From the balanced equation above,
2 moles of H2O2 decomposed to produce 1 mole of O2.
Therefore, Xmol of H2O2 will decompose to produce 7.81×10¯³ mole of O2 i.e
Xmol of H2O2 = 2 x 7.81×10¯³
Xmol of H2O2 = 1.562×10¯² mole
Therefore, 1.562×10¯² mole of H2O2 decomposed in the reaction.
Finally, we shall convert 1.562×10¯² mole of H2O2 to grams. This is illustrated below:
Molar mass of H2O2 = (2x1) + (16x2) = 34g/mol
Mole of H2O2 = 1.562×10¯² mole
Mass of H2O2 =..?
Mole = mass /Molar mass
1.562×10¯² = mass /34
Cross multiply
Mass of H2O2 = 1.562×10¯² x 34
Mass of H2O2 = 0.53g
Therefore, 0.53g of Hydrogen peroxide, H2O2 were decomposition in the reaction.