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For each of the following acid-base reactions, calculate how many grams of each acid are necessary to completely react with and neutralize 2.4 g of the base.HCl(aq)+NaOH(aq)→H2O(l)+NaCl(aq)

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Answer:


m_(HCl)=2.19gHCl

Step-by-step explanation:

Hello,

In this case, for the reaction between hydrochloric acid and sodium hydroxide, for 2.4 g of base, we can compute the neutralized grams of acid by applying the 1:1 molar ratio between them and their molar masses, 36.45 g/mol and 40 g/mol respectively as shown below by stoichiometry:


m_(HCl)=2.4gNaOH*(1molNaOH)/(40gNaOH)*(1molHCl)/(1molNaOH)*(36.45gHCl)/(1molHCl)\\ \\m_(HCl)=2.19gHCl

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