Question

A circuit contains a 40 ohm resistor and a 60 ohms resistor connected in parallel. If you test this circuit with a DMM you should read a total resistance

Answer 1

24 ohms

Step-by-step explanation:

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Answer 2

24Ω

Step-by-step explanation:

When resistors are connected in parallel, the reciprocal of their combined resistance, when read with a DMM (Digital Multimeter - for measuring various properties of a circuit or circuit element such as resistance...) is the sum of the reciprocals of their individual resistances.

For example if two resistors of resistances R₁ and R₂ are connected together in parallel, the reciprocal of their combined resistance Rₓ is given by;

`(1)/(R_x)` =
`(1)/(R_1)` +
`(1)/(R_2)`

Solving for Rₓ gives;

`R_(x)` =
`(R_1 * R_2)/(R_1 + R_2)` ------------------(i)

From the question;

Let

R₁ = resistance of first resistor = 40Ω

R₂ = resistance of second resistor = 60Ω

Now,

To get their combined or total resistance, Rₓ, substitute these values into equation (i) as follows;

`R_(x)` =
`(40 * 60)/(40 + 60)`

`R_(x)` =
`(2400)/(100)`

`R_(x)` = 24 Ω

Therefore, the total resistance is 24Ω