Answer:
![HI_(_a_q_)~+~NaHCO_3_(_a_q_)~->~NaI_(_a_q_)~+~H_2O_(_l_)~+~CO_2_(_g_)](https://img.qammunity.org/2021/formulas/chemistry/college/raluot58wzocaix5n8ymj3kb399vahxq0e.png)
Step-by-step explanation:
In this case, we will have a neutralization reaction. We have a base (
) and a base (
). Additionally, we have a strong acid and a strong base, therefore both will be soluble on water, so we will have an aqueous state for these compounds. If we will have a neutralization reaction, we will have as a salt as a product. With this in mind the reaction would be:
![HI_(_a_q_)~+~NaHCO_3_(_a_q_)~->~NaI_(_a_q_)~+~H_2O_(_l_)~+~CO_2_(_g_)](https://img.qammunity.org/2021/formulas/chemistry/college/raluot58wzocaix5n8ymj3kb399vahxq0e.png)
All the sodium salts are soluble in water, therefore we will have an aqueous state. Water is a liquid and carbon dioxide is a gas.
I hope it helps!