Question

Pls Answer it I will Mark BRAIN LIST.
​

Answer 1

cosA = 40/41

tanA = 9/40

Explanation:

Step 1: Find the other leg value

a² + b² = c²

9² + b² = 41²

b² = 41² - 9²

b = √1600

b = 40

Step 2: Draw out your triangle.

When you do so, you should see the cosA (adjacent over hypotenuse) is 40/41 and tanA (opposite over adjacent) is 9/40.

Triangle CBA

Length of AC = 40 (Leg)

Length of BC = 9 (Leg)

Length of AD = 41 (Hypotenuse)

cosA = AC/AB = 40/41

tanA = CB/AC = 9/40

Answer 2

Cos A = 40/41

Tan A = 9/40

Explanation:

Sin A =
`(perpendicular)/(hypotenuse)` =
`(9)/(41)`

So,

Perpendicular = 9 , Hypotenuse = 41

So, Finding base by Pythagorean Theorem

=>
`c^2=a^2+b^2`

=>
`a^2 = c^2-b^2\\`

=>
`a^2 = 41^2-9^2`

=>
`a^2 = 1681 - 81\\a^2 = 1600`

Taking sqrt

=> base = 40

Now,

Cos A =
`(base)/(hypotenuse) = (40)/(41)`

Tan A =
`(perpendicular)/(base) = (9)/(40)`