Question

A 120-V rms voltage at 60.0 Hz is applied across an inductor, a capacitor, and a resistor in series. If the peak current in this circuit is 0.8484 A, what is the impedance of this circuit

Answer 1

200
`\Omega`

Step-by-step explanation:

The computation of the impedance of the circuit is shown below:

Provided that

RMS voltage = 120 v

Frequency = 60.0 Hz

RMS current = 0.600 A

Based on the above information, the formula to compute the impedance is

`Z=(V_(max))/(I_(peak))`

where,

`V_(max) = √(2) * V_(rms)`

`= √(2) * 120`

`= 169.7 V`

And,
`I_Peak = 0.8484`

Now placing these above values to the formula

So, the impedance of the circuit is

`= (169.7)/(0.8484)`

= 200
`\Omega`