Answer:
The energy of a single photon of X‑rays is
![E_v = 52898.9 \ eV](https://img.qammunity.org/2021/formulas/physics/college/ebyb2ew744uembial8lflceag0ubhk6m24.png)
Step-by-step explanation:
From the question we are told that
The mass of the tissue is
![m = 175 \ g = 0.175 \ kg](https://img.qammunity.org/2021/formulas/physics/college/1q6w8mah2n6g4sfn2utvhetqhbv9cgvy11.png)
The amount of energy delivered is
![E_T = 4.05 \mu J = 4.05 *10^(-6) \ J](https://img.qammunity.org/2021/formulas/physics/college/8krodhv3ryecjwifxconus8xj988s0wuaw.png)
The wavelength is
![\lambda = 0.0235 \ nm = 0.0235 *10^(-9) \ m](https://img.qammunity.org/2021/formulas/physics/college/en2ush3a1ovf65yrsitxe5v8fyw3s2mk7z.png)
Generally the energy of a single photon is mathematically represented as
![E = (hc)/(\lambda )](https://img.qammunity.org/2021/formulas/physics/college/s2rl4knx686kte6srerlql7zlglu3014ps.png)
Where h is the Planck's constant with values
![h = 6.63 *10^(-34)\ J\cdot s](https://img.qammunity.org/2021/formulas/physics/college/ao5r5eftice7mp4gzzq5oihk6vyc9mo2sq.png)
and c is the speed of light with values
![c = 3.0 *10^(8) \ m/s](https://img.qammunity.org/2021/formulas/physics/college/n9ylmx4m92nu4uwxzxt0691rdz7t1diqhx.png)
Substituting values
![E = (6.63 *10^(-34) * 3.0*10^(8))/(0.0235 *10^(-9) )](https://img.qammunity.org/2021/formulas/physics/college/avuf7x3lahsxw9aai6ke0zw2fzzq6z5fjw.png)
![E = 8.463 *10^(-15) \ J](https://img.qammunity.org/2021/formulas/physics/college/i5bnvi5gu98qvbgprro6vdqln8u8yr9ln2.png)
Converting this to electron volt we have
![E_v = 8.464 *10^(-15) * [(1 )/(1.6*10^(-19)) ]](https://img.qammunity.org/2021/formulas/physics/college/z41cjh81iqvioqa82y5sk39pcvegb7xept.png)
![E_v = 52898.9 \ eV](https://img.qammunity.org/2021/formulas/physics/college/ebyb2ew744uembial8lflceag0ubhk6m24.png)