166k views
2 votes
ZABD and ZCBD are adjacent. Given that m_ABC is 68º. MZABD= (2x + 5)º, and mZCBD= (3x+8)º, find mZCBD.

A. 11°
B. 22°
C. 25°
D. 410
Please select the best answer from the choices provided

1 Answer

3 votes

Answer:

I think that the required options are wrong.

Answer is given below with explanations.

mZCBD = 41 degrees

Explanation:


from \: the \: \: above \: mentioned \: diagram \\ we \: can \: say \: that \: \\( angle \: ABD) + (angle \: DBC) = 68 \\ given \: that \: \: angle \: ABD = 2x + 5 \\ and \: \: angle \: CBD = 3x + 8 \\ on \: substituting \: the \: values \\ (2x + 5) + (3x + 8) = 68 \\ 5x + 13 = 68 \\ 5x = 68 - 13 \\ 5x = 55 \\ x = (55)/(5) \\ x = 11 \\ angle \: CBD = 3x + 8 \\ \: \: = 3(11) + 8 \\ \: \: = 33 + 8 \\ \: \: angle \: CBD= 41

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION.

ZABD and ZCBD are adjacent. Given that m_ABC is 68º. MZABD= (2x + 5)º, and mZCBD= (3x-example-1
User Colin Claverie
by
4.5k points