Question

The drawing shows a top view of a hockey puck as it slides across frictionless ice. Three forces act on the puck, and it is in equilibrium. The force F is applied at the center and has a magnitude of 32 N. The force F1 is applied at the top edge, and F2 is applied half way between the center and the bottom edge. Find the magnitude of F1 and F2.

Answer 1

The values of the forces are

`F_1 = 10.6 \ N` ,
`F_2 = 21.33 \ N`

Step-by-step explanation:

The diagram for this question is shown on the first uploaded image

From the question we are told that

The magnitude of F is
`F = 32 \ N`

Generally at equilibrium the torque is mathematically evaluated as

`\sum \tau = 0`

From the diagram we have

`r * F_1 - [(r)/(2) ] F_2 + 0 F = 0`

=>
`F_1 = 0.5 F_2`

Generally at equilibrium the Force is mathematically evaluated as

`\sum F = 0`

From the diagram

`F - F_ 1 - F_2 = 0`

substituting values

`32 - (0.5F_2 ) - F_2 = 0`

`F_2 = 21.33 \ N`

So

`F_1 = 0.5 * 21.33`

`F_1 = 10.6 \ N`