Question

A metal plate of 400 mm in length, 200mm in width and 30 mm in depth is to be machined by orthogonal cutting using a tool of width 5mm and a depth of cut of 0.5 mm. Estimate the minimum time required to reduce the depth of the plate by 20 mm

Answer 1

the minimum time required to reduce the depth of the plate by 20 mm is 26 minutes 40 seconds

Step-by-step explanation:

From the given information;

Assuming the tool moves 100 mm/sec

The number of passes required to reduce the depth from 30 mm to 20 mm can be calculated as:

Number of passes =
`(30-20)/(0.5)`

Number of passes = 20

We know that the width of the tool is 5 mm; therefore, to reduce the depth per pass; the tool have to travel 20 times

However; the time per passes is;

Time/pass =
`(20*L)/(velocity \ of \ the \ feed)`

where;

length L = 400mm

velocity of the feed is assumed as 100

Time/pass
`=(20*400)/(100)`

Time/pass = 80 sec

Thus; the minimum time required to reduce the depth of the plate by 20 mm can be estimated as:

`T_(min) = Time/pass *number of passes`

`T_(min) = 20*80`

`T_(min) = 1600 \ sec`

`T_(min)` = 26 minutes 40 seconds

Answer 2

Complete Question:

A metal plate of 400 mm in length, 200mm in width and 30 mm in depth is to be machined by orthogonal cutting using a tool of width 5mm and a depth of cut of 0.5 mm. Estimate the minimum time required to reduce the depth of the plate by 20 mm if the tool moves at 400 mm per second.

Answer:

`T_(min) =` 26 mins 40 secs

Step-by-step explanation:

Reduction in depth, Δd = 20 mm

Depth of cut,
`d_c = 0.5 mm`

Number of passes necessary for this reduction,
`n = (\triangle d)/(d_c)`

n = 20/0.5

n = 40 passes

Tool width, w = 5 mm

Width of metal plate, W = 200 mm

For a reduction in the depth per pass, tool will travel W/w = 200/5 = 40 times

Speed of tool, v = 100 mm/s

`Time/pass = (40*400)/(400) \\Time/pass = 40 sec`

minimum time required to reduce the depth of the plate by 20 mm:

`T_(min) =` number of passes * Time/pass

`T_(min) =` n * Time/pass

`T_(min) =` 40 * 40

`T_(min) =` 1600 = 26 mins 40 secs