Question

Find the number of real number solutions for the equation. x2 + 5x + 7 = 0 0 2 1 cannot be determined

Answer 1

0 solution

Explanation:

Given

`x^2 + 5x+ 7 = 0`

Required

Find number of solutions;

The number of solutions can be determined via the value of determinants, D;

Such that

`D = {b^2} - {4ac}`

By comparing the general form of equation;

`ax^2 +bc x + c = 0`

with
`x^2 + 5x+ 7 = 0`

This gives

`a = 1\\b = 5\\c = 7`

So;

`D = {b^2} - {4ac}` becomes

`D = {5^2} - {4*1*7}`

`D = {25} - {28}`

`D = -3`

The calculated value of D is less than 0;

This implies that
`x^2 + 5x+ 7 = 0` has no real solution