Question

A box weighing 180 newtons is hanging by rope as shown in the figure. Find the tension T2.

Answer 1

The question is incomplete, however, the correct question is attached

in the image format:

Answer:

B. 171 N

Explanation:

The equation of the forces along the

Horizontal direction:

`T_(2) cos62^(0) = T_(1) cos20^(0)`...... 1

Verticalb direction:

`T_(1) sin20^(0) = T_(2) sin62^(0)` = W . . . 2

Where W = 180 N is the weight of the box.

From equation (1),

`= T_(1) =T_(2) (cos62^(0))/( cos20^(0))`

Substituting into equation (2),

`(T_(2) (cos62^(0))/( cos20^(0)))`
`sin20^(0) = T_(2) sin62^(0)`

=
`T = (W)/(cos62x^(0) tan20x^(0)+sin62x^(0) )`

=117 N

Thus, the correct answer is option B. 117 N