Question

Andre and scott share the driving on a trip. Scott drives 7 miles more than three times tge distance Andre drives. If the trip is 111 miles, what distance did scott drive?

Answer 1

Scott drove 89.5 miles.

Explanation:

Represent Andre's distance by a and Scott's by s. Then s = 3a + 7.

Then the total distance driven by both is a + 3a + 7 = 117 (miles), or

4a - 110 miles, or a = 27.5 miles. Thus, s = 3(27.5) + 7 = 89.5 miles.

Answer 2

Explanation:

What we know is that A + S = 111. That is, the miles Andre drove plus the miles Scott drove totalled 111 miles. What we also know is that Scott drove quite a bit more than Andre did. Scott drove 7 miles more that ( +7 ) 3 times the number of miles Andrea drove. That looks like this algebraically:

S = 3A + 7

Now we can sub in that value for S to the original equation:

If A + S = 111 and S = 3A + 7, then

A + 3A + 7 = 111 and

4A + 7 = 111 and

4A = 104 so

A = 26 and

S = 3(26) + 7 so

S = 85 miles.

Scott drove 85 miles.