Question

A self-contained breathing apparatus can be a life-saving piece of personal protective equipment (PPE) for first responders. SCBA provide breathing oxygen in a contained system for use in low-oxygen environments or in the presence of toxic fumes. The oxygen is generated through the reaction of potassium superoxide, KO2 and carbon dioxide, forming potassium carbonate and oxygen gas. If the 25.0 g KO2 in the SCBA system was exposed to 45.0 g CO2, what scenario best describes the outcome:

Answer 1

Therefore , 37.27g of CO₂ unreacted or remained because KO₂ is limiting

Step-by-step explanation:

The balanced chemical equation is

`4K0_2(s) + 2CO_2(g) \rightarrow 2K_2CO_3(s) + 3O_2(g`

we calculate the moles of KO₂ and CO₂

`Moles=(Mass)/(Molecular\:mass)`

Moles of KO₂ = 25.0/71.1 = 0.3516 moles

Moles of CO₂ = 45.0/44 = 1.0227 moles

`4K0_2(s) + 2CO_2(g) \rightarrow 2K_2CO_3(s) + 3O_2(g`

1 mole of KO₂ requires 1/2 mole of CO₂

0.3516 moles of KO₂ requires
`=(1)/(2) *0.3516=0.1758`

∴ no of mole of CO₂ required to complete reaction is 0.1758 moles

Avalaible no of mole of CO₂ is 1.0227 moles

∴ The exces no of mole of CO₂ is 1.0227 - 0.1758

= 0.8469 moles of CO₂

∴ mass of CO₂ that did not react is

no of mole x molar mass

=0.8469 x 44.01

= 37.27g of CO₂

Therefore , 37.27g of CO₂ unreacted or remained because KO₂ is limiting