Answer:
a) From the empirical rule we know that within 3 deviations from the mean we have 99.7% of the data
b)
![P(191.5<X<319.5)](https://img.qammunity.org/2021/formulas/mathematics/college/pea3mxq8vbe6ptwit8lmdm4m8gceppabdt.png)
We can find the number of deviations from the mean for the limits using the z score formula given by:
![z=(x-\mu)/(\sigma)](https://img.qammunity.org/2021/formulas/mathematics/high-school/24k01r9qa0a6ibv4tds8q1jpbjh932http.png)
And replacing we got:
![z=(191.5-255.4)/(63.9)= -1](https://img.qammunity.org/2021/formulas/mathematics/college/2bn34ep1nesrg0sw01efqkanbw1bsbez4s.png)
![z=(319.3-255.4)/(63.9)= 1](https://img.qammunity.org/2021/formulas/mathematics/college/418z6408yh517reyyt6a3exhgve9etryfk.png)
So we have values within 1 deviation from the mean and using the empirical rule we know that we have 68% of the values for this case
Explanation:
For this case we have the following properties for the random variable of interest "blood platelet counts"
represent the mean
represent the population deviation
Part a
From the empirical rule we know that within 3 deviations from the mean we have 99.7% of the data
Part b
We want this probability:
![P(191.5<X<319.5)](https://img.qammunity.org/2021/formulas/mathematics/college/pea3mxq8vbe6ptwit8lmdm4m8gceppabdt.png)
We can find the number of deviations from the mean for the limits using the z score formula given by:
![z=(x-\mu)/(\sigma)](https://img.qammunity.org/2021/formulas/mathematics/high-school/24k01r9qa0a6ibv4tds8q1jpbjh932http.png)
And replacing we got:
![z=(191.5-255.4)/(63.9)= -1](https://img.qammunity.org/2021/formulas/mathematics/college/2bn34ep1nesrg0sw01efqkanbw1bsbez4s.png)
![z=(319.3-255.4)/(63.9)= 1](https://img.qammunity.org/2021/formulas/mathematics/college/418z6408yh517reyyt6a3exhgve9etryfk.png)
So we have values within 1 deviation from the mean and using the empirical rule we know that we have 68% of the values for this case