Answer:
m∠AOC= 120°
, m∠BOD = 130°
m∠COE = 110°
m∠COD.= 60°
Explanation:
Let's note that
AOF = COD= 60°
BOC = FOE= 70°
AOB = DOE= 50°
Given: m∠AOB=50°, m∠FOE=70°. m∠AOC
, m∠BOD,
m∠COE
m∠COD. = AOF = (360-(2(70)+2(50)))/2
AOF = (360-240)/2
AOF = 120/2
AOF = 60°= COD
COE = COD+DOE= 60+50= 110°
BOD = BOC + COD = 70+60= 130°
AOC = AOB + BOC = 50+70 = 120°