Question

Please answer if you know
5y^2 - 2 = 3y

Answer 1

y= -2/5 and y=1

Explanation:

Start by transforming the equation to your liking:

`5y^2-2=3y\\5y^2-3y-2=0\\`

Now we have to factor! To do this we have to find common numbers. Do this by multiplying -2 and 5 to get -10. Now think about which two numbers add multiply to be -10 but also add up to be -3 (I got this number from the middle of the equation). The two numbers you should've got are -5 and 2.

Now substitute those two number in place of the middle term, which is -3y like so:

`5y^2-5y+2y-2 =0`

Now solve the equation in pieces... find the greatest common factor from
`(5y^2-5y)` and the greatest common factor from
`(2y-2)` . The two common factors for both of those are 5y and 2. Your equation should now look like this:

`5y(y-1)` +
`2(y-1)`

The two greatest common factors become into one group and the other equation that they have in common (y-1) is it's own equation:

`(5y+2)(y-1)=0`

Now equal both of the equations to 0 and solve for y to get both of the values of y.