Question

Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approximately 57.0 m . If the track is completely flat and the race car is traveling at a constant 26.5 m/s (about 59 mph ) around the turn, what is the race car's centripetal (radial) acceleration

Answer 1

The centripetal acceleration of the car will be 12.32 m/s² .

Step-by-step explanation:

Given that

radius ,R= 57 m

Velocity , V=26.5 m/s

We know that centripetal acceleration given as follows

`a_c=(V^2)/(R)`

Now by putting the values in the above equation we get

`a_c=(26.5^2)/(57)=12.32\ m/s^2`

Therefore the centripetal acceleration of the car will be 12.32 m/s² .