Question

a scientist prepares a solution by dissolving 25.22g of lithium fluoride (lif) in 2.2 liters of water. What would be the molarity of the solution?

Answer 1

`c = 0.441mol{dm}^( - 1)`

Step-by-step explanation:

`m = 25.22g \\ v = 2.2l = 2.2 {cm}^(3) \\ mm(lif ) = 7 + 19 \\ = 26g {mol}^( - 1) \\ number \: of \: moles(n) = (m)/(mm) \\ = \frac{25.22g}{26g {mol}^( - 1) } \\ = 0.97mol \\ concetration(c) = (n)/(v) \\ = \frac{0.97mol}{2.2 {cm}^(3) } \\ c = 0.441mol {dm}^( - 3)`