Question

A gas sample that has a pressure of 4.23 atm, a volume of 1,870 mL, and a temperature of 293 K is allowed to expand to a volume of 6.01 L with a final temperature of 373 K. What is the final pressure of the gas in atmospheres?

Answer 1

1.68 atm.

Step-by-step explanation:

Given:

P1 = 4.23atm

V1 = 1870 mL

T1 = 293K

P2 = ?

V2 = 6.01 L = 6010 mL

T2 = 373 K

Assuming number of moles and R is constant:

`(P1V1)/(T1) = (P2V2)/(T2)`

⇒ P2 =
`(P1V1T2)/(T1V2)` =
`(2,950,467.3)/(1,760,930)`

= 1.68 atm.