Question

If p varies jointly as q and the cube

of r, and p
= 270 when q = 6 and
r = 3, find p when q = 3 and r = 5.

Answer 1

625

Explanation:

p= Kqr³

where K is the constant

K = p/qr³ = 270/6•3³

K= 5/3

p = 5/3• qr³

p = 5/3• 3• 5³

p = 5⁴

p= 625

Hope it helps! :)