Question

An 8 Ω resistor is connected to a battery. The current that flows in the circuit is 2 A. Calculate the voltage of the battery.

Answer 1

• Resistance=8Ohm=R
• Current=I=2A
• Potential difference=V

Using ohms law

`\boxed{\sf (V)/(I)=R}`

`\\ \sf\longmapsto V=IR`

`\\ \sf\longmapsto V=8(2)`

`\\ \sf\longmapsto V=16V`

Answer 2

Here is the highly detailed, arcane, complex, technical form of Ohm's Law that is needed in order to answer this question ===> V = I · R .

Voltage = (current) x (resistance)

Voltage = (2 Ampere) x (8 Ω)

Voltage = 16 volts