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The graph of an absolute value function has a vertex at (–2, 3) and passes through the point (–1, 0). Using transformations of the parent function, has the graph been dilated by a scale factor other than 1? Explain.

2 Answers

7 votes

Answer:

Yes, the graph has been dilated.

Using the standard form of the equation, substitute in the values: h = –2, k = 3, x = –1, and y = 0.

Solve the equation to get a = –3.

Graphically, the parent function follows the pattern of right 1, up 1. Moving 1 unit to the right from the vertex, you can move down 3 units to get to the point (–1, 0), so it has been horizontally compressed.

Explanation:

Explanation:

Edg 2020

User Stevehayter
by
6.6k points
3 votes

Answer:

The answer to this question can be defined as follows:

Explanation:

Given vertex:

(-2,3) and (-1,0)

finding slope:


\bold{Formula:}\\\\\bold{m=(y_2-y_1)/(x_2-x_1)}


y_2=0\\y_1=3\\x_2=-1\\x_1=-2


\ M= (0-3)/(-2-(-1))\\\\\ M= (0-3)/(-2+1)\\\\\ M= (-3)/(-1)\\\\\ M= 3

According to the slope value, its value is greater than 1 that's why the graph has been dilated.

User Sorin C
by
6.8k points
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