Answer:
For the revenue per month to drop, the price per boat per month has to drop more than $2,000
Step-by-step explanation:
Given:
Number of boats sold per month = 50
Cost of each boat = $25,000
Each month demand increases at a rate of 4 boats per month.
Required:
Find the fastest price could drop before monthly revenue starts to drop.
Revenue, R = Price × Quantity
R = P × Q
Differntiate both sides with respect to time, t:
![(dR)/(dt) = (dP)/(dt) Q + (dQ)/(dt) P](https://img.qammunity.org/2021/formulas/business/college/w0pmf1y7y41jqxqmo5132k9vlabow8wele.png)
![= (dP)/(dt) 50 + 4 * 25,000](https://img.qammunity.org/2021/formulas/business/college/cjhpd808xyofrln7vxv0txeobqvlykywsj.png)
For the fastest price could drop before monthly revenue starts to drop,
![(dR)/(dt) < 0](https://img.qammunity.org/2021/formulas/business/college/5j1rd678ivrnawjzvljc67kelx91ys35uu.png)
Thus,
![= (dP)/(dt) 50 + 4 * 25,000 < 0](https://img.qammunity.org/2021/formulas/business/college/f72t31mfbreww1rd9k91yegh7mvqetze8k.png)
![= (dP)/(dt) 50 + 100,000 < 0](https://img.qammunity.org/2021/formulas/business/college/q7ikw3c76ezs9qnwuh2yfhtj02967avvwe.png)
![= (dP)/(dt) 50 < -100,000](https://img.qammunity.org/2021/formulas/business/college/6kuqbg3a547bjdz43s32i63o7n12tqnthb.png)
![(dP)/(dt) = (-100,000)/(50)](https://img.qammunity.org/2021/formulas/business/college/l95dz4rqh1krig36h767i94x7kik1vhis9.png)
![(dP)/(dt) = -2,000](https://img.qammunity.org/2021/formulas/business/college/2z1zmj68fm4coteq1h7y2ii6alu4yhncyl.png)
Since the answer is negative, it indicates a drop in price.
Therefore, for the revenue per month to drop, the price per boat per month has to drop more than $2,000