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Can someone plz help me Thank you in advance:)

Can someone plz help me Thank you in advance:)-example-1

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Answer : The specific heat of the metal is,
2178.67J/kg^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.


q_1=-q_2


m_1* c_1* (T_f-T_1)=-m_2* c_2* (T_f-T_2)

where,


c_1 = specific heat of metal = ?


c_2 = specific heat of ice =
2000J/kg^oC


m_1 = mass of metal = 1.00 kg


m_2 = mass of ice = 1.00 kg


T_f = final temperature of mixture =
-8.88^oC


T_1 = initial temperature of metal =
5.00^oC


T_2 = initial temperature of ice =
-24.0^oC

Now put all the given values in the above formula, we get:


(1.00kg)* c_1* (-8.88-5.00)^oC=-[(1.00kg)* 2000J/kg^oC* (-8.88-(-24.0))^oC]


c_1=2178.67J/kg^oC

Therefore, the specific heat of the metal is,
2178.67J/kg^oC

User Jasttim
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