Question

Can someone plz help me Thank you in advance:)

Answer 1

Answer : The specific heat of the metal is,
`2178.67J/kg^oC`

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

`q_1=-q_2`

`m_1* c_1* (T_f-T_1)=-m_2* c_2* (T_f-T_2)`

where,

`c_1` = specific heat of metal = ?

`c_2` = specific heat of ice =
`2000J/kg^oC`

`m_1` = mass of metal = 1.00 kg

`m_2` = mass of ice = 1.00 kg

`T_f` = final temperature of mixture =
`-8.88^oC`

`T_1` = initial temperature of metal =
`5.00^oC`

`T_2` = initial temperature of ice =
`-24.0^oC`

Now put all the given values in the above formula, we get:

`(1.00kg)* c_1* (-8.88-5.00)^oC=-[(1.00kg)* 2000J/kg^oC* (-8.88-(-24.0))^oC]`

`c_1=2178.67J/kg^oC`

Therefore, the specific heat of the metal is,
`2178.67J/kg^oC`