The given question is incomplete, the complete question is:
A 10.0 L tank at 28.6 C is filled with 5.67 g of sulfur tetrafluoride gas and 4.66 g of carbon monoxide gas. You can assume both gases behave as ideal gases under these conditions. Calculate the total pressure in the tank. Round each of your answers to 3 significant digits.
Answer:
The correct answer is 0.541 atm.
Step-by-step explanation:
Based on the given information, 5.67 grams of sulfur tetrafluoride gas and 4.66 grams of CO gas is filled in the tank having the capacity of 10 liters at 28.6 degree C or 273 + 28.6 = 301.6 K. The no. of moles can be determined by using the formula, n = weight/molecular mass.
The moles of sulfur tetrafluoride = 5.67 grams / 108 gram per mole (The molecular mass of SF4 is 108 g/mol)
= 0.0525 moles
Similarly the moles of CO = 4.66 grams / 28 gram per mole (The molecular mass of CO is 28 g/mol)
= 0.166 moles
The sum of the moles = 0.0525 + 0.166 = 0.2185 moles
The total pressure can be calculated by using the formula,
P = nRT/V
Here n is 0.2185 moles, R is 0.0821 L.atm/mol.K, T is 301.6 K and V is 10 Liters. Now putting the values we get,
P = 0.2185 moles * 0.0821 L.atm/mol.K * 301.6 K / 10 L
P = 0.541 atm