Question

Solve the quadratic equation 3x²+2x-4=0

Answer 1

Explanation:

Hello,

`\Delta = 2^2-4*3*(-4)= 4+48=52`

so the two solutions are

`(-2+2√(13))/(2*3)=(√(13)-1)/(3)=0.87\\\\(-2-2√(13))/(2*3)=-(√(13)+1)/(3)=-1.54\\\\`