Answer:
30.48g of N2H4
Step-by-step explanation:
Step 1:
The balanced equation for the reaction. This is given below:
N2H4 + 7H2O2 → 2HNO3 + 8H2O
Step 2:
Determination of the mass of N2H4 that reacted and the mass HNO3 produced from the balanced equation. This is illustrated below:
Molar mass of N2H4 = (14x2) + (4x1) = 32g/mol
Mass of N2H4 from the balanced equation = 1 x 32 = 32g
Molar Mass of HNO3 = 1 + 14 + (16x3) = 63g/mol
Mass of HNO3 from the balanced equation = 2 x 63 = 126g
Summary:
From the balanced equation above,
32g of N2H4 reacted to produce 126g of HNO3.
Step 3:
Determination of the mass of N2H4 required to produce 120g of HNO3. This is illustrated below:
From the balanced equation above,
32g of N2H4 reacted to produce 126g of HNO3.
Therefore, Xg of N2H4 will react to produce 120g of HNO3 i.e
Xg of N2H4 = (32 x 120)/126
Xg of N2H4 = 30.48g
Therefore, 30.48g of N2H4 is required to produce 120g of HNO3.