Question

A line is drawn through the point (-1,-1), parallel to the line 2x-3y+9=0. Where will it cross the x-axis?

Answer 1

^^^^^^^^^^^^^^^^^^**^^^^^^^^^^^^^

Answer 2

2x-3y-1=0

I hope I'm correct.

Explanation:

`2x-3y+9=0\\Rearrange -in-form-of : y = mx+b\\-3y=0-9-2x\\-3y=-2x-9\\(-3y=-2x-9)/(-3) \\y =(2)/(3) \\\\For- parallelism- , m1=m2\\One -point- form (-1,-1)\\x1 = -1\\y1 = -1 \\m = (2)/(3)\\ y -y1=m(x-x1)\\y -(-1)=(2)/(3) (x-(-1))\\y+1=(2)/(3)(x+1)\\y+1=(2)/(3)x + (2)/(3)\\\\y = (2)/(3)x + (2)/(3)-1\\\\y = (2)/(3)x - (1)/(3)\\Multiply- through-: by 3 \\3[y = (2)/(3)x - (1)/(3)]\\\\3y = 2x -1\\Answer = 2x-3y-1=0`