Question

FAST PLEASE

What is the surface area of the triangular prism? A triangular prism. The base is 6 feet by 9 feet. The 2 rectangular sides are 9 feet by 5 feet. The triangular sides have a base of 6 feet and height of 4 feet. square feet

Answer 1

A ≈ 208.28

Explanation:

A ≈ 208.28

a Base side 6

b Base side 9

c Base side 5

h Height 9

Now you have to use the formulas:

A = 2
`A_(B)` + (a+b+c) h

`A_(B)` = √ s (s﹣a) (s﹣b) (s﹣c)

s =
`(a + b + c)/(2)`

Solving for A:

A = a h + b h + c h +
`(1)/(2)`﹣√
`a^(4)` +
`2(ab)^(2)` +
`2(ac)^(2)` ﹣
`b^(4)` +
`2(bc)^(2)`﹣
`c^(4)`

= 6 · 9 + 9 · 9 + 5 · 9 +
`(1)/(2)` · √﹣
`6^(4\\)` + 2 ·
`(6*9)^(2)` + 2 ·
`(6*5)^(2)`﹣
`9^(4)` + 2 ·
`(9*5)^(2)` ﹣
`5^(4)`

≈ 208.28427

Answer 2

SA = 169 feet

Explanation:

Surface Area of triangular prism = b₁h₁+2b₂h₂ + b₃h₃

Where b₁ is the base of triangular side(6 ft), h₁ is the height of triangular side (4 ft), b₂ is the base of rectangular side (9 ft), h₂ is the height of rectangular side(5 ft), b₃ is the base of the base(6 ft), h₃ is the height of the base(4 ft).

SA =
`(6*4)+2(9*5)+(6*9)`

SA = 24+90+54

SA = 169 feet