Question

Write the equation of the line that is parallel to the given segment and that passes through the point (-3,0).

A. y=-3x + 9
B.
-1
y = -X-1
3
C.
1
y=-x+1
D. y = 3x - 1

Answer 1

Option (B)

Explanation:

In the figure attached,

A straight line is passing through two points (0, 2) and (3, 1).

Slope of this line (
`m_1`) =
`(y_2-y_1)/(x_2-x_1)`

=
`(2-1)/(0-3)`

=
`-(1)/(3)`

Let the slope of a parallel to the line given in the graph =
`m_2`

By the property of parallel lines,

`m_1=m_2`

`m_2=-(1)/(3)`

Equation of a line passing through a point (x', y') and slope 'm' is,

y - y' = m(x - x')

Therefore, equation of the parallel line which passes through (-3, 0) and having slope =
`-(1)/(3)` will be,

`y-0=-(1)/(3)(x+3)`

`y=-(1)/(3)x-1`

Option (B). will be the answer.