132k views
4 votes
Write the equation of the line that is parallel to the given segment and that passes through the point (-3,0).

A. y=-3x + 9
B.
-1
y = -X-1
3
C.
1
y=-x+1
D. y = 3x - 1

Write the equation of the line that is parallel to the given segment and that passes-example-1

1 Answer

3 votes

Answer:

Option (B)

Explanation:

In the figure attached,

A straight line is passing through two points (0, 2) and (3, 1).

Slope of this line (
m_1) =
(y_2-y_1)/(x_2-x_1)

=
(2-1)/(0-3)

=
-(1)/(3)

Let the slope of a parallel to the line given in the graph =
m_2

By the property of parallel lines,


m_1=m_2


m_2=-(1)/(3)

Equation of a line passing through a point (x', y') and slope 'm' is,

y - y' = m(x - x')

Therefore, equation of the parallel line which passes through (-3, 0) and having slope =
-(1)/(3) will be,


y-0=-(1)/(3)(x+3)


y=-(1)/(3)x-1

Option (B). will be the answer.

User Bryan Grezeszak
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.