Question

4. An airplane is traveling at a speed of 724 km/hr at a direction of 30 degrees. The wind is blowing from the west at 32 km/hr. Find the resultant speed and true course of the plane.

Answer 1

28.8

Explanation:

Answer 2

28.8 degrees bearing above from the east.

Explanation:

Given :

Direction =30 degrees

Speed =724 km/hr

Suppose x1, y1 be the velocity bearing in the east at the 30 degree

so x1 velocity = 724 cos 30 degree

y1 velocity = 724 sin 30 degree

As mention in the question the wind speed adding another 32 to the x1 speed.

Hence the resultant speed is

`velx1= 659\\vely1 = 362`

`The \ speed\ is\ determined \ by \ following\ formula\ \\ √(vel y1^2+ velx1^2) \\= √(659^2+362^2)\\=751.9 km/hr\\therefore\ \ the\ direction is\ arctan \\= vely1/ velx1 \\= arctan( 362/659) \ =28.8\ degrees\ above\ from\ the\ east`