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I need help with 3 and 4

I need help with 3 and 4-example-1

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\huge \underbrace \mathfrak \red{Answer}

To find :-

To get the value of 'di in figure 3 and 4.

Figure 3

  • According to the figure, we know that it is a quadrilateral.
  • It's all sides are at 90°.
  • So we can assume that it can be rectangle.
  • In the figure, length of one side is given and area of figure is given and we have the length of another side.

Solution :-

Area of rectangle = length × width

area = 108 ft², length = 12 ft, width = x


108 = 12 * x \\ (108)/(12) = x \\ 9 = x

  • Therefore, the value of x in this figure is 9 ft.


\\

Figure 4

  • According to figure, we finds out that it is quadrilateral as it has 4 sides.
  • It has all parallel sides.
  • We can assume that it is parallelogram as the sides which are facing each other are parallels.
  • And here value of one side is given which is base and area is given, we have to find here is height.

Solution :-

Area of parallelogram = base × height

Area = 96 cm², base = 16 cm, height = x


96 = 16 * x \\ (96)/(16) = x \\ 6 = x

  • Therefore, the value of x is 6 cm.
User Joknawe
by
7.8k points
5 votes

Answer:


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( 3 )

the given figure resembles a rectangle !

now ,


Area \: of \: rectangle = length * breadth \\ \\ given \: - \: length = 12 \: ft \\ \therefore \:breadth = x \: ft \\ \\ Area = 108 \: ft {}^(2) \\ \\ \implies \: length * breadth = 108 \: ft {}^(2) \\ \\ \implies \: x * 12 = 108 \\ \\ \implies \: x = \cancel(108)/(12) \\ \\ \bold\red{\implies \: x = 9 \: ft}

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( 4 )

the given figure resembles a parallelogram!


Area \: of \: parallelogram = height * base \\ \\ \implies \: height = x \: cm\\ \\ \implies \: base = 16 \: cm \\ \\ \: Area \: = 96 \: cm {}^(2) \\ \\ \implies \: x * 16 = 96 \\ \\ \implies \: x = \cancel(96)/(16) \\ \\ \bold\red{\implies \: x = 6 \: cm}

hope helpful :D

User Amit Tumkur
by
9.0k points

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