Question

Got the ans thanks neede coz i had doubt but got clarified

Answer 1

i. 170 m

ii. 850 m

Step-by-step explanation:

Question

Arjun and his son Arav were standing ‘x’ m away from each other. They are equidistant (Y m) from a vertical cliff. Arjun burst a balloon and Arav heard the direct sound 0.5 seconds later and the echo after 2 seconds. If the speed of sound in air is 340m/s ,calculate

i. the distance between Arjun and Arav

ii. the distance between the cliff and Arjun

The parameters given are;

The time for the sound to reach Arav,
`t_D` = 0.5 s

Time for the echo to echo to reach Arav,
`t_E` = 2 s

The distance between Arjun and Arav =
`D_D`

The distance between Arav and the cliff =
`D_E`

The speed of sound in air, s = 340 m/s

The formula for speed, s, is
`s = (Distance, D)/(Time, t)`, therefore;

`s = (D_D)/(t_D) = (D_D)/(0.5) = 340`

`D_D` = 0.5 s × 340 m/s = 170 m

The distance between Arjun and Arav = 170 m

ii. Since Arav hears the direct sound before the echo, he is closer to the cliff than Arjun, therefore, we have;

`s = (D_E)/(t_E) = (D_E)/(2) = 340`

`D_E` = 2 s × 340 m/s = 680 m

Therefore, the distance between Arav and the cliff = 680 m

Which gives the distance between the cliff and Arjun,
`D_(cliff)` = The distance between Arav and the cliff + The distance between Arjun and Arav

`D_(cliff)` = 680 + 170 = 850 m.