Answer:
Formula for the large diameter =
D = TL/ 12 + d
Where
T = Taper per foot in inches/foot
L = Length in inches
d = small diameter in inches.
The large diameter = 12.0625 inches
Explanation:
Looking at the above question, we are told that a machinist is needs a Taper cylindrical shank.
Taper in machinery can be defined as what is used to attach the bit of a tool to the spindle of a machine. Taper when used in machinery operates using the principle of friction.
To calculate the Taper in a machinery, we use the formula:
T = (D - d)/ L × 12
T = Taper in inches/foot
D = Large diameter in inches
d = small diameter in inches
L = Length of the Taper in inches
From the above question, we are asked to find the Large diameter of the cylindrical tapered shank.
The formula for the large diameter can be derived from the Formula for a Taper
Since,
T = (D - d)/ L × 12
We would divide both sides by 12
= T/12 = (D - d) /L
Cross Multiply
= (T × L)/ 12 = D - d
D = (T × L)/ 12 + d
Hence, the formula for the large diameter =
D = TL/ 12 + d
Where
T = Taper per foot in inches/foot
L = Length in inches
d = small diameter in inches.
In the question, we are given:
Taper per foot = 0.75inches per foot
The small diameter = 11 inches
The length = 17 inches.
Hence,
Large diameter (D) = (0.75 × 17)/ 12 + 11
The large diameter = 12.0625 inches