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What is the value of x in the equation (StartFraction one-half EndFractionx + 12) = StartFraction one-half EndFraction(StartFraction 2 Over 3 EndFraction left-parenthesis StartFraction one-half EndFraction. x plus 12 right-parenthesis equals left-parenthesis StartFraction one-half EndFraction left-parenthesis StartFraction one-third EndFraction x plus 14 right-parenthesis minus 3.x + 14) – 3?

–24
–6
negative StartFraction 2 Over 3 EndFraction.
0

User Troelskn
by
4.2k points

2 Answers

1 vote

Answer: option A. -24

Explanation:

User Sww
by
3.9k points
4 votes

Answer:


x = -24

Explanation:

Your question is not well presented

Given


(2)/(3)((1)/(2)x + 12) = (1)/(2)((1)/(3)x + 14) - 3

Required

Solve for x


(2)/(3)((1)/(2)x + 12) = (1)/(2)((1)/(3)x + 14) - 3

Open Brackets


(2)/(3)*(1)/(2)x + (2)/(3)*12 = (1)/(2)*(1)/(3)x +(1)/(2)* 14 - 3


(1)/(3)x + (2*12)/(3) = (1)/(6)x +(14)/(2) - 3


(1)/(3)x + (24)/(3) = (1)/(6)x +(14)/(2) - 3


(1)/(3)x + 8 = (1)/(6)x +7 - 3

Collect Like Terms


(1)/(3)x - (1)/(6)x= 7 - 3 - 8


(1)/(3)x - (1)/(6)x= -4

Take LCM


(2-1)/(6)x= -4


(1)/(6)x= -4

Multiply both sides by 6


6*(1)/(6)x= -4*6


x= -4*6


x = -24

User Steven Hammons
by
4.1k points