Question

Find the magnitude of the torque that acts on the molecule when it is immersed in a uniform electric field of 6.19×105 N/C with its electric dipole vector at an angle of 69.9∘ from the direction of the field.

Answer 1

The torque exerted on a molecule in a uniform electric field can be calculated using the formula T = μEsinθ. In this case, the magnitude of the electric field is 6.19×10^5 N/C and the angle is 69.9°.

Step-by-step explanation:

The torque exerted on a molecule in a uniform electric field can be calculated using the formula:

T = μEsinθ

Where T is the torque, μ is the electric dipole moment, E is the magnitude of the electric field, and θ is the angle between the dipole moment and the electric field.

In this case, the magnitude of the electric field is given as 6.19×105 N/C and the angle is 69.9°. Therefore, the magnitude of the torque can be calculated as:

T = μ(6.19×105 N/C)sin(69.9°)

Answer 2

`\tau=5.81* 10^5p\ N-m`

Step-by-step explanation:

We have,

Electric field,
`E=6.19* 10^5\ N/C`

The electric dipole vector at an angle of 69.9 degrees from the direction of the field.

The torque acting on a molecule is given by :

`\tau=p* E\\\\\tau=pE\sin\theta`

p is electric dipole moment

`\tau=p* 6.19* 10^(5)* \sin (69.9)\\\\\tau=5.81* 10^5p\ N-m`

So, the magnitude of the torque acting on the molecule is
`5.81* 10^5p\ N-m`.