Question

The net of a square pyramid is shown below: Net of a square pyramid showing 4 triangles and the square base. The square base has side lengths of 2 inches. The height of each triangle attached to the square is 5 inches. The base of the triangle is the side of the square. What is the surface area of the solid?

Answer 1

24 in²

Explanation:

Surface area= Area of square + 4* Area of triangle

Side of square= 2 in

Base of triangle= 2 in

Height of triangle= 5 in

Surface area= 2² + 4*1/2*2*5= 24 in²

Answer 2

`\huge\boxed{\sf 24\ in.\²}`

Explanation:

Formulas to be used:

• 
  `Area\ of\ square = Length * length`
• 
  `\displaystyle Area\ of\ triangle = (1)/(2) (Base)(Height)`

Solution:

A square pyramid consists of 1 square and 4 triangles.

So,

Surface Area of Pyramid = Area of Square + 4(Area of Triangle)

Where,

Base/Length = 2 in.

Height = 5 in.

So,

Area of square:

= 2 × 2

= 4 in.²

Area of triangle:

= 1/2 (2)(5)

= 5 in.²

Surface Area of Pyramid:

= Area of square + 4(Area of triangle)

= 4 + 4(5)

= 4 + 20

= 24 in.²

`\rule[225]{225}{2}`