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What is the area of the irregular polygon shown below?

18
F
3.5
18
O A. 60 sq. units
B. 86 sq. units
C. 79 sq. units
D. 100 sq. units

User Sshturma
by
4.9k points

2 Answers

4 votes

Answer:

Option B: 49 square units.

Explanation:

User Nimbudew
by
5.1k points
2 votes

Answer:

Option B: 49 square units.

Explanation:

The irregular polygon consists of a rhombus a square.

Area of rhombus = 0.5*(product of diagonals).

Area of square = length * length = l^2.

The diagonals of the rhombus measure 8 units and 6 units respectively. The diagram shows the length of half of the diagonals, so doubling both the lengths gives us the required lengths. The side of the square measures 5 units. Substituting all the information in the formula:

Total Area = Area of rhombus + Area of square.

Total Area = 0.5*8*6 + 5^2.

Total Area = 24 + 25

Total Area = 49 square units.

Option B is correct! Hope this helps! :)