Answer:
f(x) = 3sin(3.1416(x +4)/7)
Explanation:
You want the equation of a sine function with an amplitude of 3 and having one cycle between the points (-11, 0) and (3, 0), where it has negative slope.
Equation
The equation will generally be of the form ...
f(x) = (amplitude)·sin(2π/(period)·(x-(horizontal translation)))
Application
Here, the amplitude is 3 units, the period is (3 -(-11)) = 14 units, and the horizontal translation from the origin to the positive-going midline crossing is 4 units to the left.
Then f(x) is ...
f(x) = 3·sin(2π/14(x -(-4))
f(x) = 3·sin(3.1416/7(x +4))
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