Question

Ahoy starting from rest moves with a distance of 200m in 10 seconds...Find the magnitude of acceleration

Answer 1

The magnitude of acceleration is 2m/s² .

Step-by-step explanation:

First, you have to find the velocity as it starts to travel 200m in 10s. The formula of velocity is V = Distance/Time, then you have to substitute the values into the formula :

`v = d / t`

`let \: d = 200 \\ let \: t = 10`

`v = 200 / 10`

`v = 20m/s`

Next, you have to substitute the values into the acceleration formula, a = (v-u)/t where v represents final velocity, u is initial velocity and t is time taken :

`a = (v - u)/(t)`

`let \: v = 20 \\ let \: u = 0 \\ let \: t = 10`

`a = (20 - 0)/(10)`

`a = (20)/(10)`

`a = 2m/ {s}^(2)`