Question

Air flows steadily through a variable sized duct in a heat transfer experiment with a speed of u = 20 – 2x, where x is the distance along the duct in meters, and u is in m/s. Because of heat transfer out of the duct, the air temperature, T, within the pipe cools as it goes downstream, according to T = 200 - 5x C. As they flow past the section at x= 3 meters, (a) determine the acceleration; (b) Determine the rate of change of temperature of air particles

Answer 1

a)
`a=-28m/s^(2)`

b)
`(dT)/(dx)=-5 ^(o)C/m`

Step-by-step explanation:

a)

In order to solve this problem, we need to start by remembering how the acceleration is related to the velocity of a particle. We have the following relation:

`a=(dv)/(dt)`

in other words, the acceleration is defined to be the derivative of the velocity function with respect to time. So let's take our speed function:

u=20-2x

if we take its derivative we get:

du=-2dx

this is the same as writting:

`(du)/(dt)=-2(dx)/(dt)`

we also know that velocity is defined to be:

`u=(dx)/(dt)`

so we get that:

a=-2u

when substituting we get that:

a=-2(20-2x)

when expanding we get:

a=-40+4x

and now we can use this equation to find our acceleration at x=3, so:

a=-40+4(3)

a=-40+12

`a=-28 m/s^(2)`

b)

the same applies to this problem with the difference that this will be the rate of change of the temperature per m. So we proceed and take the derivative of the temperature function:

T=200-5x

`(dT)/(dx)=-5`

so the rate of change is
`-5^(o)C/m`