124k views
0 votes
Amy worked 16 hours more than Brayden last month. If Amy worked 8 hours for every 7 hours that Brayden worked, how many hours did they each work? (round answers to 1 decimal place) Amy worked hours Brayden worked hours

1 Answer

3 votes

Answer:

Amy worked for 128 hours while Brayden worked for 112 hours

Explanation:

Given

Let A represents Amy and B represents Brayden

A = 16 + B ------(1)

A:B = 8:7------- (2)

Required

Find A and B;

Convert (2) to fractions


(A)/(B) = (8)/(7)

Cross Multiply


7 * A = 8 * B


7A = 8B

Substitute A = 16 + B in the above expression


7(16 + B) = 8B

Open Bracket


7 * 16 + 7 * B = 8B


112 + 7B = 8B

Subtract 7B from both sides


112 + 7B - 7B = 8B - 7B


112 = B


B = 112

Recall that A = 16 + B

Hence,
A = 16 + 112


A = 128

This implies that Amy worked for 128 hours while Brayden worked for 112 hours

User IanG
by
8.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories