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Ide length

Recall that in a 30° -60° - 90° triangle, if the shortest leg


measures x units, then the longer leg measures x/5 units


and the hypotenuse measures 2x units.


(150/3 – 757) ita


(300 - 757) ft


(150/3 - 257) ft


(300 - 257) ft?



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User Giuppep
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5.6k points

2 Answers

7 votes

Answer:

it’s A

Explanation:

i took the test

User Stephanea
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6 votes

Question Correction

A circle is inscribed in a regular hexagon with side length 10 feet. What is the area of the shaded region? Recall that in a 30–60–90 triangle, if the shortest leg measures x units, then the longer leg measures
x√(3) units and the hypotenuse measures 2x units.


  • (150√(3)-75\pi) $ ft^2
  • (300 – 75π)
    ft^2

  • (150√(3)-25\pi) $ ft^2
  • (300 – 25π) ft2

Answer:

(A)
(150√(3)-75\pi) $ Square Units

Explanation:

Area of the Shaded region =Area of Hexagon-Area of the Circle

Area of Hexagon

Length of the shorter Leg = x ft

Side Length of the Hexagon =10 feet

Perimeter of the Hexagon = 10*6 =60 feet

Apothem of the Hexagon (Length of the longer leg)

=
x√(3) feet


=5√(3)$ feet


\text{Area of a Regular hexagon}=(1)/(2) * $Perimeter * $Apothem


=(1)/(2) * 60 * 5√(3)\\=150√(3)$ Square feet

Area of Circle

The radius of the Circle = Apothem of the Hexagon
=5√(3)$ feet

Area of the Circle


=(5√(3))^2 * \pi\\ =25 * 3 * \pi\\=75\pi $ Square feet

Therefore:

Area of the Shaded region
= (150√(3)-75\pi) $ Square feet

Ide length Recall that in a 30° -60° - 90° triangle, if the shortest leg measures-example-1
User Clark Fitzgerald
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