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X intercept f(x)=(x+4)^2

1 Answer

4 votes

Answer:

-4

Explanation:

Given the function f(x)=(x+4)², the x intercept occurs at f(x) = 0, substituting f(x) = 0 into the given equation to get the value of x we have;


0 = (x+4)^(2) \\

Taking the square root of both sides


√((x+4))^(2) = √(0)\\ x+4 = 0\\

Subtracting 4 from both sides of the equation


x+4-4 = 0-4\\x = -4

Therefore the x intercept of the equation is -4

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